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-0.546x^2+0.577x+2=0
a = -0.546; b = 0.577; c = +2;
Δ = b2-4ac
Δ = 0.5772-4·(-0.546)·2
Δ = 4.700929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.577)-\sqrt{4.700929}}{2*-0.546}=\frac{-0.577-\sqrt{4.700929}}{-1.092} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.577)+\sqrt{4.700929}}{2*-0.546}=\frac{-0.577+\sqrt{4.700929}}{-1.092} $
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